Help with a swmming math problem

Former Member
Former Member
Mathematically, how do you work out 'three quarter pace"? Let's say (for the sake of easy calculations) your best time for an event is 1 minute. In practice, you want to go three quarter pace. So a 100% effort will result in a time of 60 seconds. A 75% effort should result in a longer time. My rudimentary maths tells me I should divide 100 by 75 and multiply the result by 60. That works out to 80 seconds, which is a minute and 20 seconds. Why does that sound much slower than what I would normally envisage three quarter pace to be? Or is my maths completely messed up?
Parents
  • Former Member
    Former Member
    Thanks for the review. I do not think there is a mistake when I expand out the terms: P_swim = ((C_flow * V^2) * D_pool) * t_interval keeping in mind V = D_pool / t_interval let us now substitute terms for V P_swim = ((C_flow * (D_pool/t_interval)^2) * D_pool) * t_interval one of the t_interval's gets canceled out.
Reply
  • Former Member
    Former Member
    Thanks for the review. I do not think there is a mistake when I expand out the terms: P_swim = ((C_flow * V^2) * D_pool) * t_interval keeping in mind V = D_pool / t_interval let us now substitute terms for V P_swim = ((C_flow * (D_pool/t_interval)^2) * D_pool) * t_interval one of the t_interval's gets canceled out.
Children
No Data