Help with a swmming math problem

Former Member
Former Member
Mathematically, how do you work out 'three quarter pace"? Let's say (for the sake of easy calculations) your best time for an event is 1 minute. In practice, you want to go three quarter pace. So a 100% effort will result in a time of 60 seconds. A 75% effort should result in a longer time. My rudimentary maths tells me I should divide 100 by 75 and multiply the result by 60. That works out to 80 seconds, which is a minute and 20 seconds. Why does that sound much slower than what I would normally envisage three quarter pace to be? Or is my maths completely messed up?
Parents
  • Former Member
    Former Member
    Great topic for discussion Perhaps we should consider the two separate issues: - Physiological response to exercise stress (i.e. heart rate, repirotory rate, lactic acid build up etc.) - Power resistance "curve" provided by swimming activity The power resistance "curve" for swimming activity would be where you could find the answer to the original question of a 3/4 pace swim to simulate competition effort. Hydrodyanamic drag of a swimmer body through the water increases as the velocity squared. As a result, the power required to make a interval time will increase as the square of the relative change in time. Consider the following equations F_drag = C_flow * V^2 V_swim = d_swim/t_interval W_swim = F_drag * D_pool P_swim = W_swim * t_interval where: F_drag - hydrodyamic drag of swimmer body through water V_swim - swimmer velocity through water d_swim - pool distance swum t_interval - competition time or training pace interval W_swim - work expenditure of swimmer. This quantity is directly related to required caloric intake to recover from swim workout P_swim - power expenditure of swimmer. This quantity is related to swimmer bodies capability to convert chemical energy stores into usefull muscular power output I put in the term C_flow as a constant that would represent an individuals flow resistance in the water. It considers skin friction, form drag and stroke efficiency. You would determine your personal C_flow number from swim tests. You might have one C_flow for sloppy swimming and one for high quality ;) If you take all these equations and combine you could get the following: P_race = C_flow * (d_swim^2 / t_race) So if you consider C_flow and d_swim the same between train and race conditions and wanted an interval that was three quarter (75%) of your race speed power output you would just have. t_train = t_race/0.75 You were correct in your original answer. For me the challenge that engages me in those long sets of training intervals is working toward keeping efficiency high (make C_flow low) for strokes and turns and to simulate short periods of race conditions in training to monitor any changes in C_flow. Happy swimming.
Reply
  • Former Member
    Former Member
    Great topic for discussion Perhaps we should consider the two separate issues: - Physiological response to exercise stress (i.e. heart rate, repirotory rate, lactic acid build up etc.) - Power resistance "curve" provided by swimming activity The power resistance "curve" for swimming activity would be where you could find the answer to the original question of a 3/4 pace swim to simulate competition effort. Hydrodyanamic drag of a swimmer body through the water increases as the velocity squared. As a result, the power required to make a interval time will increase as the square of the relative change in time. Consider the following equations F_drag = C_flow * V^2 V_swim = d_swim/t_interval W_swim = F_drag * D_pool P_swim = W_swim * t_interval where: F_drag - hydrodyamic drag of swimmer body through water V_swim - swimmer velocity through water d_swim - pool distance swum t_interval - competition time or training pace interval W_swim - work expenditure of swimmer. This quantity is directly related to required caloric intake to recover from swim workout P_swim - power expenditure of swimmer. This quantity is related to swimmer bodies capability to convert chemical energy stores into usefull muscular power output I put in the term C_flow as a constant that would represent an individuals flow resistance in the water. It considers skin friction, form drag and stroke efficiency. You would determine your personal C_flow number from swim tests. You might have one C_flow for sloppy swimming and one for high quality ;) If you take all these equations and combine you could get the following: P_race = C_flow * (d_swim^2 / t_race) So if you consider C_flow and d_swim the same between train and race conditions and wanted an interval that was three quarter (75%) of your race speed power output you would just have. t_train = t_race/0.75 You were correct in your original answer. For me the challenge that engages me in those long sets of training intervals is working toward keeping efficiency high (make C_flow low) for strokes and turns and to simulate short periods of race conditions in training to monitor any changes in C_flow. Happy swimming.
Children
No Data