Where does the power occur?

Former Member
Former Member
A while back, I jumped on the triathlon website Slowtwitch and got attacked for saying that the power in the freestyle pull comes in the front of the stroke (hand entry to shoulder), not in the middle (shoulder to belly button) or back (belly button to release). Nonsense...they said. Didn't you read the article by Popov's coach showing the power is at the end of the stroke? That never made sense to me. After all, at the end of the stroke there is only about one muscle still working, the tricep, and the hand is not in that position for very long. At last, I got the proof I needed. A few weeks ago I was tested on the Velocity Meter, a very cool device that measures the speed of the body through the entire stroke cycle. It was VERY revealing and provided tons of information I could not get elsewhere. Such as:1) the body speed slows by as much as 40% from the fastest to the slowest point during a single arm stroke. 40%!!! That is huge. The difference in speed is directly caused by the body going from a relative streamlined position to a very non-streamlined position and back again. 2) The fastest point in the stroke cycle is when the hand first enters the water and the slowest point is when the hand is about at the shoulder underwater. That is when the upper arm is pointing nearly perpendicular to the line of the body (ie most drag). I realize that the speed of the body at any given instant is a result of the propulsive power minus the drag forces, that one cannot determine just from the velocity that the power is really greater in front. But when the speed drops from 2.5 meters per second when the hand is in front to 1.4 meters per second when it is in the middle, I have to believe that the power in front is greatest. By the way, the propulsive power of the arm is created by both lift forces at the beginning and drag forces in the middle, as the hand shifts from forward motion to backward motion (then forward again as it releases). Anyway, read my latest blog on our website www.theraceclub.com to find out more revealing secrets from the Velocity Meter. Gary Sr.
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  • Former Member
    Former Member
    Chris: if you agree that distance per stroke = speed divided by stroke rate, then at 34 strokes for 50 meters, we don't have the same DPS or the same SR. The DPS and the SR are below: Lezak: 50 meters in 23 seconds = 2.17 meters per second 34 strokes in 23 seconds = 1 stroke every .67 seconds MJM: 50 meters in 35 seconds = 1.42 meters per second 34 strokes in 35 seconds = 1 stroke every 1.02 seconds Lezak: 2.17 meters per sec./.67 strokes per second. DPS = 3.23 meters MJM: 1.42 meters per sec./1.02 strokes per second. DPS = 1.39 meters So I should have said Lezak and I can take the same number of strokes for 50 meters. However, his stroke rate combined with his distance per stroke is not something I will achieve in my lifetime. --mjm:bow:
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  • Former Member
    Former Member
    Chris: if you agree that distance per stroke = speed divided by stroke rate, then at 34 strokes for 50 meters, we don't have the same DPS or the same SR. The DPS and the SR are below: Lezak: 50 meters in 23 seconds = 2.17 meters per second 34 strokes in 23 seconds = 1 stroke every .67 seconds MJM: 50 meters in 35 seconds = 1.42 meters per second 34 strokes in 35 seconds = 1 stroke every 1.02 seconds Lezak: 2.17 meters per sec./.67 strokes per second. DPS = 3.23 meters MJM: 1.42 meters per sec./1.02 strokes per second. DPS = 1.39 meters So I should have said Lezak and I can take the same number of strokes for 50 meters. However, his stroke rate combined with his distance per stroke is not something I will achieve in my lifetime. --mjm:bow:
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